Sobes.tech
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```java public class DoWork { public static void main(String[] args) { work(); } public static void work() { try { work(); } finally { work(); } } } ```

sobes.tech AI

Answer from AI

This code contains an infinite recursion, which will lead to a stack overflow (StackOverflowError).

Explanation:

  • The work() method calls itself within the try block.
  • After the try block completes, the finally block executes, which again calls work().

Thus, each call to work() results in two new calls: one in the try block and one in the finally block, leading to exponential growth of calls and rapid stack overflow.

Example of an error when running:

Exception in thread "main" java.lang.StackOverflowError
    at DoWork.work(DoWork.java:...)
    ...

Such code should not be used without exit conditions for the recursion.

```java public class DoWork { public static void… - sobes.tech