Senior
```java public class DoWork { public static void main(String[] args) { work(); } public static void work() { try { work(); } finally { work(); } } } ```
sobes.tech AI
Answer from AI
This code contains an infinite recursion, which will lead to a stack overflow (StackOverflowError).
Explanation:
- The
work()method calls itself within thetryblock. - After the
tryblock completes, thefinallyblock executes, which again callswork().
Thus, each call to work() results in two new calls: one in the try block and one in the finally block, leading to exponential growth of calls and rapid stack overflow.
Example of an error when running:
Exception in thread "main" java.lang.StackOverflowError
at DoWork.work(DoWork.java:...)
...
Such code should not be used without exit conditions for the recursion.