# 1 a = [1, 2, 3] b = a b.append(4) # print(a) # print(a is b) # 2 a = 10 b = a # print(a is b) b += 5 # print(a) # print(b) #3 # data = { # ([1, 2, 3]): "a", # (1, 2, 3): "b" # } # print(data) #4 a = (1, [2, 3]) # a[1].append(4) # print(a) #5 a = [1, 2, 2, 3] b = set(a) # print(len(a), len(b))
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Answer from AI
Let's analyze each block of code and its behavior:
a = [1, 2, 3]
b = a
b.append(4)
print(a) # [1, 2, 3, 4]
print(a is b) # True
Lists are mutable objects. Variables a and b refer to the same object. Changes through b are reflected in a. The is operator shows that they are the same object.
a = 10
b = a
print(a is b) # True (for small integers in Python)
b += 5
print(a) # 10
print(b) # 15
Integers are immutable objects. When doing b += 5, a new object is created, and b now refers to 15, while a remains 10. is may be True for small numbers due to interning.
data = {
([1, 2, 3]): "a",
(1, 2, 3): "b"
}
print(data)
Dictionary keys must be hashable. The list [1,2,3] is mutable and unhashable, so this will raise a TypeError: unhashable type: 'list'. The tuple (1,2,3) is hashable and valid.
a = (1, [2, 3])
a[1].append(4)
print(a) # (1, [2, 3, 4])
A tuple is immutable, but if it contains mutable objects (like a list), their contents can be changed. Here, the list inside the tuple is modified.
a = [1, 2, 2, 3]
b = set(a)
print(len(a), len(b)) # 4 3
A set contains only unique elements. The list has 4 elements, while the set has 3 unique elements.
In summary: it's important to understand the differences between mutable and immutable objects, reference and value semantics, and the requirements for dictionary keys.