What will happen to the hashCode method's result if the class does not explicitly override it?

If a class does not explicitly override the hashCode() method, the implementation from the Object class is used. In this case, hashCode() returns an integer value that is usually based on the internal address of the object in memory (or another unique identifier of the JVM).

This means that different objects, even if they are logically equal, will have different hash codes, which can lead to incorrect behavior of hash structures (e.g., HashMap or HashSet) if hashCode() and equals() are not overridden.

Example:

Object obj1 = new Object();
Object obj2 = new Object();
System.out.println(obj1.hashCode()); // unique number
System.out.println(obj2.hashCode()); // different unique number