func main() { c := make(chan int, 1000) var wg sync.WaitGroup wg.Add(100) for i := 0; i < 100; i++ { go func() { defer wg.Done() foo(c) }() } go func() { wg.Wait() close(c) }() sum := 0 for r := range c { sum += r } // fmt.Println(sum) } func foo_req(c chan int) error { r := rand.Int() for i := 0; i < r; i++ { c <- r } }
sobes.tech AI
Answer from AI
The provided code has several issues:
-
In the
foo_reqfunction (which callsfooin the code but is defined asfoo_req), there is a write to the channelcin a loop from 0 tor, whereris a random number. This can lead to blocking if the channel buffer overflows, since the channel is buffered for 1000 elements, andrcan be larger. -
In the goroutine that runs
foo, the parameteriis not passed, but this is not critical sinceiis not used inside. -
The
foo_reqfunction does not return an error, althougherroris declared. -
In
main, there is correct waiting for all goroutines to finish viaWaitGroupand closing the channel.
To avoid blocking, ensure that the number of elements sent to the channel does not exceed its buffer, or use non-blocking send or additional synchronization.
Example fix for the foo function:
func foo(c chan int) {
r := rand.Intn(1000) // limit maximum
for i := 0; i < r; i++ {
c <- r
}
}
Or use non-blocking send with select:
func foo(c chan int) {
r := rand.Intn(1000)
for i := 0; i < r; i++ {
select {
case c <- r:
default:
// channel is full, handle situation
}
}
}
Also, check that rand is initialized, and fix any inconsistencies in function names.