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If all model scores are multiplied by 2, will the ROC AUC change?

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Answer from AI

If two objects are equal according to equals() and have the same hashCode(), but different identityHashCode(), then when inserted into a HashMap, they will be considered as the same key.

HashMap uses the methods equals() and hashCode() to determine key equality and to place keys into buckets. identityHashCode() is a hash based on the object's memory address and does not affect HashMap's behavior.

Therefore:

  • When inserting a second object with the same hashCode and equal to the first object according to equals(), it will replace the value associated with the first key.
  • The HashMap will not have two entries with these keys, as they are considered equal.

Example:

Map<Object, String> map = new HashMap<>();
Object key1 = ...; // equals and hashCode match key2
Object key2 = ...;

map.put(key1, "value1");
map.put(key2, "value2"); // replaces the value for key1

System.out.println(map.size()); // 1
System.out.println(map.get(key1)); // "value2"

Thus, identityHashCode does not influence HashMap's behavior; only equals and hashCode are important.

If all model scores are multiplied by 2, will the ROC… - sobes.tech