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What is the estimated memory required to store a single byte primitive in a LinkedList data structure?

sobes.tech AI

Answer from AI

Memory estimate for storing a primitive byte in LinkedList<Byte>:

  1. Primitive byte: Takes 1 byte by itself.
  2. Wrapper object Byte: In LinkedList, objects are stored, not primitives. byte will be automatically boxed into a Byte object. The Byte object contains:
    • Object metadata (header): Usually 8 or 12 bytes (depends on JVM).
    • value field: 1 byte (for the actual byte value).
    • Padding/Alignment: Objects are often aligned to the size of a machine word (4 or 8 bytes). If the header is 12 bytes + value 1 byte = 13 bytes, it will likely be aligned to 16 bytes.
  3. LinkedList.Node node: Each element in LinkedList is wrapped in an instance of the inner class Node. This node contains:
    • Object metadata (header): 8 or 12 bytes.
    • item field: Reference to the stored object (Byte). Reference size is usually 4 or 8 bytes (depending on 32- or 64-bit JVM and compressed oops).
    • next field: Reference to the next node. 4 or 8 bytes.
    • prev field: Reference to the previous node. 4 or 8 bytes.
    • Padding/Alignment: The total size of fields and header is also aligned.

Minimum estimate (32-bit JVM without compressed oops):

  • Byte object: 12 bytes (header) + 1 byte (value) + 3 bytes (padding) = ~16 bytes.
  • Node: 12 bytes (header) + 4 bytes (item reference) + 4 bytes (next reference) + 4 bytes (prev reference) + 4 bytes (padding) = ~28 bytes.
  • Total size: ~16 (Byte) + ~28 (Node) = ~44 bytes.

Typical estimate (64-bit JVM with compressed oops - default for heap < 32GB):

  • Byte object: 12 bytes (header) + 1 byte (value) + 3 bytes (padding) = ~16 bytes.
  • Node: 12 bytes (header) + 4 bytes (item reference) + 4 bytes (next reference) + 4 bytes (prev reference) + 0 bytes (padding if fields are aligned to 8 bytes) = ~24 bytes.
  • Total size: ~16 (Byte) + ~24 (Node) = ~40 bytes.

Maximum estimate (64-bit JVM without compressed oops):

  • Byte object: 12 bytes (header) + 1 byte (value) + 3 bytes (padding) = ~16 bytes.
  • Node: 12 bytes (header) + 8 bytes (item reference) + 8 bytes (next reference) + 8 bytes (prev reference) + 4 bytes (padding) = ~40 bytes (or 36+4).
  • Total size: ~16 (Byte) + ~40 (Node) = ~56 bytes.

Thus, the memory estimate for storing a single byte primitive in LinkedList<Byte> is approximately 40-60 bytes due to overheads of the Byte wrapper object and LinkedList.Node. This is significantly larger than 1 byte of the primitive itself.