Middle
What needs to be done for a user structure to become a key in a dictionary?
sobes.tech AI
Answer from AI
It is necessary to implement the Hashable protocol.
The Hashable protocol inherits from Equatable.
Equatable: Requires the implementation of the equality operator==to compare two instances of a structure.Hashable: Requires the implementation of thehash(into:)property, which computes a hash value for an instance of the structure.
Example implementation:
struct Coordinate: Hashable {
let x: Int
let y: Int
// MARK: - Equatable
static func == (lhs: Coordinate, rhs: Coordinate) -> Bool {
return lhs.x == rhs.x && lhs.y == rhs.y
}
// MARK: - Hashable
func hash(into hasher: inout Hasher) {
hasher.combine(x)
hasher.combine(y)
}
}
// Usage in a dictionary
let coordinatesDictionary: [Coordinate: String] = [
Coordinate(x: 0, y: 0): "Origin",
Coordinate(x: 1, y: 1): "Point (1,1)"
]
print(coordinatesDictionary[Coordinate(x: 0, y: 0)]!)
Hasher is used to generate a hash value. The combine method takes various hashable values and combines them to create the final hash.