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func revert(nums []int) { // 1 2 3 4 => 4 3 2 1 } func main() { a := []int{1,2,3,4,5} revert(a) fmt.Println(a) } func revert(nums []int) { // 1 2 3 4 => 4 3 2 1 l, r := 0, len(nums)-1 for l < r { nums[l], nums[r] = nums[r], nums[l] l++ r-- } } func main() { a := []int{1,2,3,4,5} revert(a) fmt.Println(a) }

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Answer from AI

The provided code snippet shows a revert function that takes a slice nums and reverses the order of its elements using two pointers — one starting at the beginning and the other at the end of the slice. While the left pointer is less than the right, elements are swapped, and the pointers move towards each other.

Example code in Go:

package main

import "fmt"

func revert(nums []int) {
    l, r := 0, len(nums)-1
    for l < r {
        nums[l], nums[r] = nums[r], nums[l]
        l++
        r--
    }
}

func main() {
    a := []int{1, 2, 3, 4, 5}
    revert(a)
    fmt.Println(a) // Output: [5 4 3 2 1]
}

Since slices in Go are passed by reference, changes inside the function affect the original slice, which is demonstrated by the output.

func revert(nums []int) { // 1 2 3 4 => 4 3 2 1 }… - sobes.tech