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It is required to implement the uniqRandn function, which generates a slice of length n of unique, random numbers. import ( "fmt" "math/rand" ) func main() { fmt.Println(uniqRandn(10)) } func uniqRandn(n int) []int { //... }
sobes.tech AI
Answer from AI
To generate a slice of n unique random numbers, you can use the following approach:
- Create a slice with numbers from 0 to m (where m >= n, for example m = n*10 or another suitable value).
- Shuffle the slice using the Fisher-Yates algorithm.
- Take the first n elements.
If the range is unlimited, you can use a map to check for uniqueness, but this is less efficient.
Example implementation:
import (
"fmt"
"math/rand"
"time"
)
func uniqRandn(n int) []int {
// Assume the range of numbers from 0 to n*10
max := n * 10
nums := make([]int, max)
for i := 0; i < max; i++ {
nums[i] = i
}
rand.Seed(time.Now().UnixNano())
// Shuffle the slice
for i := max - 1; i > 0; i-- {
j := rand.Intn(i + 1)
nums[i], nums[j] = nums[j], nums[i]
}
return nums[:n]
}
func main() {
fmt.Println(uniqRandn(10))
}
This code guarantees the uniqueness of the numbers and their random order.