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Task: What will the code output? ```go package main import "fmt" func main() { a := []int{1, 2, 3, 4, 5} b := a[:2] b = append(b, 100) fmt.Println(a, b) } ```
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Answer from AI
Code:
package main
import "fmt"
func main() {
a := []int{1, 2, 3, 4, 5}
b := a[:2] // b references the first two elements of a: [1, 2]
b = append(b, 100) // add 100 to slice b
fmt.Println(a, b)
}
Analysis:
- Initially,
a= [1, 2, 3, 4, 5] b := a[:2]— slicebcontains [1, 2], and its capacity is 5 (from index 0 to the end ofa)append(b, 100)adds the element 100 to sliceb. Sinceb's capacity allows expansion without allocating new memory, the element 100 is written intoa[2], thus modifying the original arraya.
After append:
abecomes [1, 2, 100, 4, 5]bbecomes [1, 2, 100]
Output:
[1 2 100 4 5] [1 2 100]
This means the element a[2] changed from 3 to 100 because b and a share the same underlying array.