What will be the output of the following code? ```javascript console.log(1); setTimeout(() => { console.log(2); }, 0); Promise.resolve().then(() => { console.log(3); }); console.log(4); setTimeout(() => { Promise.resolve().then(() => { console.log(5); }); }, 0); ```

The output will be:

1
4
3
2
5

Explanation of the output order:

1. console.log(1); — synchronous call, outputs 1.
2. setTimeout(..., 0) — places the callback in the macro task queue, executed later.
3. Promise.resolve().then(...) — places the callback in the micro task queue, which executes after the current stack but before macro tasks.
4. console.log(4); — synchronous call, outputs 4.

After the synchronous code finishes:

• Microtasks are executed: console.log(3);
• Then macro tasks from setTimeout: first console.log(2);
• The second setTimeout calls Promise.resolve().then(...), which places a microtask that executes console.log(5); after the current macro task.

Thus, the order is: 1, 4, 3, 2, 5.