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// Promise.resolve() // .then(() => console.log(1)) // // .then(() => console.log(2)) // // Promise.resolve() // .then(() => console.log(11)) // // .then(() => console.log(22)) //

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Answer from AI

In the given code, there are two promise chains, each starting with Promise.resolve(). It's important to understand the order of output in the console.

Each .then() adds a handler to the microtask queue, which executes after the current call stack.

Since both chains are created sequentially, their handlers will be placed in the microtask queue in the order they are declared.

Therefore, the output will be:

1
2
11
22

Explanation:

  • First, the first .then(() => console.log(1)) executes, printing 1.
  • Then, the next .then(() => console.log(2)) executes, printing 2.
  • After that, .then(() => console.log(11)) from the second chain executes, printing 11.
  • And finally, .then(() => console.log(22)) executes, printing 22.

If we wanted the output to be mixed or in a different order, we would need to change the structure of the promises or use setTimeout for delayed calls.