Principal
public class Main { public static void main(String[] args) { Integer a = 127; Integer b = 127; Integer c = 128; Integer d = 128; System.out.println(a == b); System.out.println(c == d); } } package main import "fmt" func main() { x := 1 defer func() { fmt.Println("defer:", x) }() x = 2 fmt.Println("now:", x) }
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Answer from AI
In Java:
Integer a = 127;
Integer b = 127;
Integer c = 128;
Integer d = 128;
System.out.println(a == b); // true
System.out.println(c == d); // false
Explanation:
Java caches Integer objects in the range from -128 to 127. Therefore, a and b refer to the same object, and the == comparison returns true. For values outside this range, new objects are created, so c == d is false.
In Go:
package main
import "fmt"
func main() {
x := 1
defer func() { fmt.Println("defer:", x) }()
x = 2
fmt.Println("now:", x)
}
The output will be:
now: 2
defer: 2
Explanation:
In Go, functions deferred with defer capture variables by reference, not by value. Therefore, when the deferred function executes, the value of x is already 2.