Middle+
D = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5} L = sorted([D[s] for s in D])
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Answer from AI
In the expression:
D = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
L = sorted([D[s] for s in D])
the following happens:
[D[s] for s in D]creates a list of the dictionaryD's values in the order of key traversal (in Python 3.7+ the order of keys is preserved, so this will be[1, 2, 3, 4, 5]).sorted(...)sorts this list in ascending order.
In this case, the list is already sorted, so L will be [1, 2, 3, 4, 5].
If the values were in a different order, sorted would guarantee an ascending sorted list of the dictionary's values.
Example:
D = {'a': 3, 'b': 1, 'c': 5}
L = sorted([D[s] for s in D]) # L will be [1, 3, 5]