What will be the result if you pass an array to a function and modify it inside the function?

In PHP, arrays are passed to functions by value, meaning a copy of the array is created. If you modify the array inside the function, these changes will not affect the original array outside the function.

Example:

function modifyArray($arr) {
    $arr[] = 'new element';
    print_r($arr);
}

$original = ['element1', 'element2'];
modifyArray($original);
print_r($original);

The output will be:

Array
(
    [0] => element1
    [1] => element2
    [2] => new element
)
Array
(
    [0] => element1
    [1] => element2
)

If you want to modify the original array inside the function, you need to pass it by reference using &:

function modifyArrayByReference(&$arr) {
    $arr[] = 'new element';
}

$original = ['element1', 'element2'];
modifyArrayByReference($original);
print_r($original);

Now, the changes will be saved to the original array.