How to pass a value from an outer scope into a closure for its use inside?

In PHP, the keyword use is used to pass a value from an external scope into a closure. It allows capturing variables from the external context and using them inside an anonymous function.

Example:

$externalVar = 10;

$closure = function() use ($externalVar) {
    echo $externalVar;
};

$closure(); // Outputs 10

If you need to modify the variable's value inside the closure, you should pass it by reference:

$count = 0;

$increment = function() use (&$count) {
    $count++;
};

$increment();
$increment();
echo $count; // Outputs 2