How many cycles are needed to sort and merge lists without lambda functions?

To sort and merge two lists without using lambda functions, usually two main loops are required:

1. Merging the lists:

   • You can simply iterate through the elements of the second list and add them to the first list (or a new list).

2. Sorting the merged list:

   • For sorting, you can use a standard algorithm (for example, insertion sort, bubble sort, or quicksort), which involves one or more nested loops.

If you use built-in sorting (for example, sort() in Python or Collections.sort() in Java), the number of loops inside the implementation is not visible, but from an algorithm perspective, it usually involves several passes.

Example in Python without lambdas:

list1 = [3, 1, 4]
list2 = [2, 5]

# Merging
combined = []
for item in list1:
    combined.append(item)
for item in list2:
    combined.append(item)

# Sorting (bubble sort)
for i in range(len(combined)):
    for j in range(0, len(combined)-i-1):
        if combined[j] > combined[j+1]:
            combined[j], combined[j+1] = combined[j+1], combined[j]

print(combined)

In total, to merge and sort without lambdas and built-in functions, usually at least two loops are required (one for merging, one or more for sorting).