What behavior will the compiler demonstrate when using checked exceptions in code?

In Java, checked exceptions require mandatory handling or declaration in the method signature. If the code calls a method that can throw a checked exception, the compiler will check that this exception is either caught in a try-catch block or declared in the method's throws clause. If not, compilation will fail.

For example:

public void readFile() throws IOException {
    // code that may throw IOException
}

public void process() {
    readFile(); // Compilation error if IOException is not handled
}

To fix this, you need to either wrap the call in a try-catch block or declare throws IOException in the process() method.

Thus, the compiler enforces explicit handling of checked exceptions, ensuring more reliable error handling during runtime.