Will a compilation error occur when dividing by zero in a try block if catch throws an exception and finally returns the string "finally"?

In Java, dividing by zero for integer types results in an ArithmeticException. If this occurs within a try block, and another exception is thrown in the catch block, and there is a return statement in the finally block, then the value from finally will be returned, and the exceptions will be suppressed.

Example:

public String test() {
    try {
        int a = 1 / 0; // ArithmeticException
    } catch (Exception e) {
        throw new RuntimeException("Error in catch");
    } finally {
        return "finally";
    }
}

In this code, the method will return the string "finally" and will not throw an exception, because the return in finally overrides exceptions from try and catch. This will not cause a compilation error, but such behavior can lead to loss of error information and is considered bad practice.