How do the some and any operators differ in condition checks or sets?

In Swift, the operators some and any are used for working with protocols but have different meanings:

• some is a keyword for indicating opaque return types. It signifies that a function returns a specific, but hidden type that conforms to a protocol. The type is fixed but not revealed.

• any is a keyword for creating existential types, meaning variables or parameters that can hold any type conforming to a protocol.

Example:

protocol Shape {
    func area() -> Double
}

struct Circle: Shape {
    var radius: Double
    func area() -> Double { return .pi * radius * radius }
}

// some Shape — returns a specific, but hidden type
func makeCircle() -> some Shape {
    return Circle(radius: 5)
}

// any Shape — can contain any type conforming to Shape
func printArea(of shape: any Shape) {
    print(shape.area())
}

Thus, some fixes a specific type, while any allows for different types conforming to the protocol.