Is it possible to perform comparison of Optional type objects in code?

In Swift, objects of type Optional can be compared with each other if the type they wrap supports comparison. For example, if you have Optional<Int>, you can use the == and != operators for comparison.

Comparison works as follows:

• If both values are nil, they are considered equal.
• If one is nil and the other is not, they are not equal.
• If both are not nil, their internal values are compared.

Example:

let a: Int? = 5
let b: Int? = 5
let c: Int? = nil

print(a == b) // true
print(a == c) // false
print(c == nil) // true

If the type does not support comparison, then Optional of that type cannot be compared directly.