What consequences will occur in the program's operation when GOMAXPROCS is set to 1 and an infinite goroutine is launched?

Setting GOMAXPROCS to 1 limits the number of OS threads that the Go scheduler can use to one thread. If you then launch an infinite goroutine, the following happens:

• All computations will be executed sequentially in one thread.
• If the infinite goroutine does not contain points where context switching occurs (e.g., blocking calls or runtime.Gosched()), other goroutines may not get execution time, leading to a "hang".
• As a result, the program may become unresponsive or work very slowly because the scheduler cannot effectively switch between goroutines.

Example:

package main

import (
    "runtime"
    "time"
    "fmt"
)

func main() {
    runtime.GOMAXPROCS(1)

    go func() {
        for {
            // infinite loop without calling runtime.Gosched()
        }
    }()

    time.Sleep(time.Second)
    fmt.Println("Program finished")
}

In this example, the main goroutine may not get execution time if the infinite goroutine does not yield control, which can lead to a hang.