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// Question 4. What will be displayed on the screen package main import "fmt" func subis(is []int) []int { return append(is, 5, 6) } func main() { is := []int{1, 2, 3, 4} subis(is[2:3]) fmt.Println(is) }

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Answer from AI

In this code, a slice is is created with elements [1, 2, 3, 4]. Then, the function subis is called with the argument is[2:3], which is a slice containing a single element — 3.

The subis function returns a new slice obtained by adding elements 5 and 6 to the passed slice.

However, the result of the subis call is not assigned anywhere, so the original slice is remains unchanged.

It is important to understand that slices in Go are structures containing a pointer to an array, a length, and a capacity. The slice is[2:3] creates a new slice pointing to a part of the is array, but with a length of 1 and a capacity depending on the original array.

The append function can modify the original array if there is enough capacity, but since the result is not used, changes are not saved.

Therefore, the output will be the original slice:

[1 2 3 4]
// Question 4. What will be displayed on the screen… - sobes.tech