How does data transfer physically occur through an unbuffered channel?

In Go, an unbuffered channel is a synchronization mechanism that blocks the sender until the receiver accepts the value, and vice versa.

Physically, data transfer occurs as follows: when a goroutine attempts to send a value to an unbuffered channel, it pauses (blocks) until another goroutine is ready to receive that value from the channel. Once the receiver is ready, the value is transferred directly through the internal pointer of the channel, and both goroutines resume work.

Thus, the channel acts as a synchronization point where data is transferred directly between the sender and receiver without intermediate storage.