Intern
Why is the structure's field usually made a pointer to the structure inside a function argument rather than a value?
sobes.tech AI
Answer from AI
In Go, function arguments are passed by value, meaning they are copied. If you pass a struct by value, a copy of that struct is used inside the function, and changes to fields will not affect the original.
To modify the fields of a struct inside a function and keep those changes after the function exits, you need to pass a pointer to the struct. Then, the function will work with the original data, not a copy.
Example:
type User struct {
Name string
}
func changeNameByValue(u User) {
u.Name = "Alice"
}
func changeNameByPointer(u *User) {
u.Name = "Bob"
}
func main() {
user := User{Name: "John"}
changeNameByValue(user)
fmt.Println(user.Name) // Will print "John" — the copy changed, not the original
changeNameByPointer(&user)
fmt.Println(user.Name) // Will print "Bob" — the original was changed
}
Thus, a pointer is needed to modify the original struct, not its copy.