Specify what output this program will produce and explain its operation considering the features of channels and goroutines. ```go func main() { ch := make(chan struct{}) ch <- struct{}{} go func() { <-ch fmt.Println("good") }() } ```

This program will lead to a deadlock and will not output anything.

Explanation:

• The channel ch is created without a buffer (make(chan struct{})), so sending and receiving must happen simultaneously.
• In the line ch <- struct{}{}, there is an attempt to send a value into the channel, but since no one is reading from the channel yet, this operation blocks.
• The next line starts a goroutine that reads from the channel and prints "good", but before this goroutine starts, the program is already blocked on sending to the channel.

Result: the program will hang on the send operation to the channel because there is no receiver, and it will not output anything.