package main import ( "fmt" ) func a(p *string) { s2 := "string2" *p = s2 } func main() { str1 := "string1" p := &str1 fmt.Println(*p) a(&p) fmt.Println(*p) }

The provided code has a compilation error because the function a expects a pointer to a string (*string), but in main, &p is passed, where p is already a pointer to a string (*string), so the type is **string.

If you fix the function call to a(p), the code will work as follows:

package main

import (
	"fmt"
)

func a(p *string) {
	s2 := "string2"
	*p = s2
}

func main() {
	str1 := "string1"

	p := &str1

	fmt.Println(*p) // Outputs: string1

	a(p) // Passing a pointer to str1

	fmt.Println(*p) // Outputs: string2
}

Explanation:

• In main, the variable str1 contains the string "string1".
• p is a pointer to str1.
• The function a takes a pointer to a string and changes the value at that pointer to "string2".
• After calling a(p), the value of str1 will change to "string2".

If you leave the call as a(&p), it would be a pointer to a pointer (**string), which does not match the function's declaration and will cause a compilation error.