// Need to modify the ap function so that 6 is included in the output slice and the slice is sorted // Important - the ap function does not return anything package main import ( "fmt" ) func main() { v := []int{3, 4, 1, 2, 5} ap(v) fmt.Println(v) // the result should be - [3 4 1 2 5 6] } func ap(arr []int) { arr = append(arr, 10) arr[5] = 6 }

In the current implementation, the ap function does not modify the original slice v because the append operation can create a new slice, and the assignment arr = append(arr, 10) only changes the local copy of arr.

To add an element and sort the slice without returning a value, you need to modify the slice by reference and use the sorting from the sort package:

package main

import (
	"fmt"
	"sort"
)

func main() {
	v := []int{3, 4, 1, 2, 5}
	ap(v)
	fmt.Println(v) // the result should be - [1 2 3 4 5 6]
}

func ap(arr []int) {
	arr = append(arr, 6) // add 6
	sort.Ints(arr)       // sort the slice
	// arr now contains [1 2 3 4 5 6]
}

However, since append can return a new slice with a different pointer, changes will not reflect on the original v in main. To fix this, you need to pass a pointer to the slice:

func ap(arr *[]int) {
	*arr = append(*arr, 6)
	sort.Ints(*arr)
}

func main() {
	v := []int{3, 4, 1, 2, 5}
	ap(&v)
	fmt.Println(v) // [1 2 3 4 5 6]
}

Thus, the ap function does not return a value but modifies the slice by pointer, adding 6 and sorting it.