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// Question 3. What will be displayed on the screen package main import "fmt" import "math" func main() { i := int32(math.Pow(2, 64)) - 1 fmt.Println(i) }

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Answer from AI

In this code, the calculation math.Pow(2, 64) is performed, which returns a float64 number equal to 2 raised to the power of 64. Then this value is cast to an int32 and 1 is subtracted from it.

However:

  • math.Pow(2, 64) equals 18446744073709551616, which does not fit into an int32 (maximum around 2.1e9).
  • Casting float64 to int32 will cause overflow and truncation of the value modulo 2^32.

As a result, int32(math.Pow(2, 64)) will be 0, because 2^64 modulo 2^32 is 0.

Therefore, i := int32(math.Pow(2, 64)) - 1 will be:

0 - 1 = -1

The output will be:

-1