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func maxPlaces(arr []int) int { maxDistance := 0 prev, first := -1, -1 for i := 0; i < len(arr); i++ { if arr[i] == 1 { if first == -1 { first = i maxDistance = max(maxDistance, i) } else { maxDistance = max(maxDistance, (i - prev) / 2) } prev = i } } maxDistance = max(maxDistance, len(arr) - 1 - prev) return maxDistance }

sobes.tech AI

Answer from AI

The maxPlaces function in Go calculates the maximum distance to the nearest element with value 1 in an array of 0s and 1s.

Algorithm idea:

  • Iterate through the array, recording the indices of elements with value 1.
  • For the first found 1, calculate the distance from the start of the array to it.
  • For subsequent 1s, calculate half the distance between the current and previous indices of 1 (since the optimal place for seating will be in the middle).
  • At the end, consider the distance from the last 1 to the end of the array.

Example:

type intSlice []int

func max(a, b int) int {
    if a > b {
        return a
    }
    return b
}

func maxPlaces(arr []int) int {
    maxDistance := 0
    prev, first := -1, -1
    for i := 0; i < len(arr); i++ {
        if arr[i] == 1 {
            if first == -1 {
                first = i
                maxDistance = max(maxDistance, i) // distance from the start
            } else {
                maxDistance = max(maxDistance, (i - prev) / 2) // half the distance between 1s
            }
            prev = i
        }
    }
    maxDistance = max(maxDistance, len(arr) - 1 - prev) // distance to the end
    return maxDistance
}

Thus, the function finds the maximum possible distance to the nearest occupied seat (1) for seating.

func maxPlaces(arr []int) int { maxDistance := 0… - sobes.tech