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Is it possible for a situation where the scheduler does not force a goroutine to yield execution?

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Answer from AI

In Go, the goroutine scheduler typically manages switching between goroutines to ensure concurrent execution. However, there can be situations where a goroutine does not yield execution if it performs a long synchronous operation without calling functions that can trigger a scheduler switch (such as system calls, I/O operations, or runtime.Gosched()).

This is because Go uses cooperative multitasking at the goroutine level: switching occurs at certain points, such as calls to blocking operations or runtime.Gosched(). If a goroutine runs an infinite loop without such points, it can 'block' the scheduler, not yielding control to other goroutines.

Example:

for {
    // if there are no calls here that can yield to the scheduler,
    // the goroutine may not yield execution to others
}

Therefore, it is recommended to insert calls to runtime.Gosched() or use channels/blocking operations to allow the scheduler to switch goroutines.

Is it possible for a situation where the scheduler… - sobes.tech