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It is required to implement the function uniqRandn, which generates a slice of length n of unique, random numbers. func main() { fmt.Println(uniqRandn(10)) } func uniqRandn(n int) []int { //... }

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Answer from AI

To generate a slice of n unique random numbers, you can use the following approach:

  1. Create a slice with numbers from 0 to m-1, where m >= n (for example, m = 2*n or more to have enough unique numbers).
  2. Shuffle the slice randomly.
  3. Take the first n elements.

Example implementation in Go:

package main

import (
    "fmt"
    "math/rand"
    "time"
)

func uniqRandn(n int) []int {
    m := n * 2 // you can increase this if you need a larger range
    nums := make([]int, m)
    for i := 0; i < m; i++ {
        nums[i] = i
    }

    rand.Seed(time.Now().UnixNano())
    rand.Shuffle(m, func(i, j int) {
        nums[i], nums[j] = nums[j], nums[i]
    })

    return nums[:n]
}

func main() {
    fmt.Println(uniqRandn(10))
}

If you need a range of numbers different from 0..m-1, you can adjust the generation of the initial slice. This approach guarantees uniqueness and randomness without repeats.

It is required to implement the function uniqRandn… - sobes.tech