Answer the questions package main import "fmt" func main() { original := []int{1, 2, 3} updated := append(original, 4) original[0] = 100 fmt.Println(original, updated) } What will the program output? [100 2 3] [1 2 3 4] [100 2 3] [100 2 3 4] [1 2 3] [1 2 3 4] [100 2 3] [1 2 3]

The program will output:

[100 2 3] [1 2 3 4]

Explanation:

• original := []int{1, 2, 3} — creates a slice with length 3 and capacity 3.
• updated := append(original, 4) — since the capacity of original equals its length, appending a new element creates a new array, and updated points to it.

However, in Go, slices are structures with a pointer to an array, a length, and a capacity. When using append:

• If the capacity allows, the element is added to the same array.
• If not, a new array is created and data is copied.

In this case, updated points to a new array, but original and updated still refer to the same underlying array for the first three elements because append copies elements but does not change the original array.

But in Go, when append exceeds capacity, a new array is created, and updated points to it, while original remains on the old array.

Then, original[0] = 100 changes the first element in original.

Let's check the output:

• original now [100 2 3]
• updated is [1 2 3 4]

Thus, the correct answer is:

[100 2 3] [1 2 3 4]