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How does the state of a hash table change when it is passed to a function as a parameter?

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Answer from AI

In Go, hash tables are implemented using the map type, which is passed to functions by reference. This means that when passing a map to a function, only a pointer to the internal data structure is copied, not the entire table.

As a result, any modifications made to the map inside the function (adding, removing, or changing elements) will be visible outside the function as well, since the same object is being modified.

Example:

func addEntry(m map[string]int, key string, value int) {
    m[key] = value
}

func main() {
    myMap := make(map[string]int)
    addEntry(myMap, "key1", 100)
    fmt.Println(myMap) // Will output: map[key1:100]
}

Thus, the state of the hash table is changed directly when passing it to a function.

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