Can a struct in Go implement an interface, and how can it be done?

Yes, in Go a struct can implement an interface. For this, the struct must have all the methods declared in the interface. In Go, implementing an interface does not require explicit declaration — if the struct has the necessary methods, it is automatically considered to implement the interface.

Example:

package main
import "fmt"

type Speaker interface {
    Speak() string
}

type Person struct {
    Name string
}

func (p Person) Speak() string {
    return "Hello, my name is " + p.Name
}

func main() {
    var s Speaker = Person{Name: "Ivan"}
    fmt.Println(s.Speak())
}

In this example, Person implements the Speaker interface because it has a Speak() method with the required signature.