Why does an outer try/catch not catch an error thrown inside a Promise

Explain why an exception thrown inside the body of a Promise is not caught by an outer try/catch block.

try {
  new Promise((resolve, reject) => {
    throw "asda";
  });
} catch (e) {
  console.log("Error", e);
}

• Inside the Promise constructor, any synchronous errors are automatically converted into a rejected promise, not thrown out as regular exceptions.
• A try/catch block can only catch errors that are thrown synchronously in the current call stack. An error that becomes a promise rejection will only be handled through .catch methods, await with try/catch inside an async function, or a rejection handler when creating the promise.
• To catch such an error, you need to add a rejection handler:

new Promise((resolve, reject) => {
  throw "asda";
}).catch(err => console.log("Caught", err));

or use async/await:

(async () => {
  try {
    await new Promise((resolve, reject) => {
      throw "asda";
    });
  } catch (e) {
    console.log("Caught", e);
  }
})();