Is it possible to make finally execute again (with the number 10), without changing the code order, but by adding something inside the function?

In JavaScript, the finally block always executes once after try and catch. To make finally execute again with the number 10 without changing the order of the code, you can call it recursively inside the function or use a loop, but this will change the logic.

However, if you cannot change the order of the code but can add inside the function, you can call a helper function inside finally that performs the needed code with the number 10. For example:

function example() {
  try {
    console.log('try block');
  } catch(e) {
    console.log('catch block');
  } finally {
    console.log('finally block');
    runAgain(10);
  }
}

function runAgain(num) {
  console.log('finally called again with', num);
}

example();

Thus, the finally block itself will run once, but inside it, you can call additional code with the desired parameter. If you need the finally block to execute again, it is impossible without changing the code order.