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const obj = [{ value: 1, elems: [ { value: 2, elems: [ { value: 3 }, { value: 6 }, ... ] }, { value: 4, elems: [ { value: 5, elems: [ { value: 6 }, ... ]} ] } ] }] ------------- setTimeout(() => { console.log(1); }, 0); const p = new Promise(resolve => { console.log(2); resolve(); }); p.then(() => { console.log(3) }).then(() => { console.log(4); }); console.log(5);
sobes.tech AI
Answer from AI
Let's consider the order of output to the console:
setTimeout(() => {
console.log(1);
}, 0);
const p = new Promise(resolve => {
console.log(2);
resolve();
});
p.then(() => { console.log(3) }).then(() => { console.log(4); });
console.log(5);
Explanation:
setTimeoutplaces the callback in the macrotask queue with a delay of 0.- When creating the promise, its executor runs immediately, so
console.log(2)is output right away. p.thenadds callbacks to the microtask queue.console.log(5)executes synchronously after the promise is created.
Output order:
- 2 (immediately upon promise creation)
- 5 (after the promise, synchronously)
- 3 (microtask from
then) - 4 (next microtask from the
thenchain) - 1 (macrotask from
setTimeout)
Result:
2
5
3
4
1