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```javascript console.log("Start"); setTimeout(() => { console.log("Timeout 1"); Promise.resolve().then(() => console.log("Promise inside Timeout")); }, 0); Promise.resolve() .then(() => { console.log("Promise 0"); setTimeout(() => console.log("Timeout inside Promise"), 0); }) .catch(() => console.log("Promise 1")) .then(() => console.log("Promise 2")); requestAnimationFrame(() => { console.log("RequestAnimationFrame"); }); console.log("End"); ```

sobes.tech AI

Answer from AI

The output will be as follows:

Start
End
Promise 0
Promise 2
Timeout 1
Promise inside Timeout
Timeout inside Promise
RequestAnimationFrame

Explanation:

  1. First, the synchronous code runs: console.log("Start") and console.log("End").
  2. Then, microtasks (microtasks) are executed — these are promises:
    • Promise.resolve().then(() => { console.log("Promise 0"); ... }) — outputs "Promise 0".
    • After that, in the chain .then(() => console.log("Promise 2")) — outputs "Promise 2".
  3. Macrotasks (macrotasks) — timeouts with setTimeout with zero delay:
    • The first setTimeout outputs "Timeout 1".
    • Inside it, a promise is created, which is placed in the microtask queue and outputs "Promise inside Timeout".
    • The second setTimeout inside the promise outputs "Timeout inside Promise".
  4. requestAnimationFrame is placed in a separate queue and executed after macrotasks, outputs "RequestAnimationFrame".

Thus, the order is based on the priorities of microtasks (promises), then macrotasks (timeouts), and finally requestAnimationFrame.

```javascript console.log("Start"); setTimeout(() =>… - sobes.tech