What will the final compiled code of a template function look like when called with arguments of different types?

When compiling a template function in C++, the compiler generates a separate version of the function (instantiates the template) for each unique set of argument types. This means that if you have a template:

template<typename T>
T add(T a, T b) {
    return a + b;
}

and you call add(1, 2) and add(1.5, 2.5), the compiler will create two separate functions:

int add(int a, int b) { return a + b; }
double add(double a, double b) { return a + b; }

Thus, the final compiled code contains specific versions of the function for each type it was called with. This allows templates to be used as generic functions without performance loss, as calls are reduced to regular functions with specific types.