import "fmt" func maxDistants(arr []int) int { maxDist := 0 lastOne := -1 for i := 0; i < len(arr); i++ { if arr[i] == 1 { if lastOne == -1 { maxDist = i } else { dist := (i - lastOne) / 2 if dist > maxDist { maxDist = dist } } lastOne = i } } if arr[len(arr)-1] == 0 { dist := len(arr) - 1 - lastOne if dist > maxDist { maxDist = dist } } return maxDist } func main() { fmt.Println(maxDistants([]int{1, 0, 0, 0, 1})) }

Go'dagi maxDistants funksiyasi 0 va 1 dan iborat massivda eng yaqin 1 gacha bo'lgan maksimal masofani hisoblaydi. G'oyasi, 1 ni joylashtirish mumkin bo'lgan pozitsiyani topishdir, shunda eng yaqin 1 ga bo'lgan masofa maksimal bo'ladi.

Mantiqni tushuntirish:

• lastOne o'zgaruvchisi oxirgi uchragan 1 ning indeksini saqlaydi.
• Massiv bo'ylab yurib, agar 1 uchrasa:
  • Agar bu birinchi 1 bo'lsa, maksimal masofa bu 1 ning indeksi (boshlang'ichdan masofa).
  • Aks holda, hozirgi va oldingi 1 orasidagi masofaning yarmini hisoblaymiz (o'rta joylashish mumkin).
• Yurishdan so'ng, oxirgi 1 ning o'ngida nolalar bor-yo'qligini tekshiramiz va kerak bo'lsa maksimal masofani yangilaymiz.

Foydalanish misoli:

package main

import "fmt"

func maxDistants(arr []int) int {
    maxDist := 0
    lastOne := -1

    for i := 0; i < len(arr); i++ {
        if arr[i] == 1 {
            if lastOne == -1 {
                maxDist = i
            } else {
                dist := (i - lastOne) / 2
                if dist > maxDist {
                    maxDist = dist
                }
            }
            lastOne = i
        }
    }
    if arr[len(arr)-1] == 0 {
        dist := len(arr) - 1 - lastOne
        if dist > maxDist {
            maxDist = dist
        }
    }
    return maxDist
}

func main() {
    fmt.Println(maxDistants([]int{1, 0, 0, 0, 1})) // 2
}

Ushbu kod massivning chekkalarini hisobga olib, eng yaqin 1 ga bo'lgan maksimal masofani to'g'ri aniqlaydi.