Millal antakse edasi initsialiseeritud muutuja väärtus defer operaatorile ja kuidas see on seotud funktsiooni nimetamisega?

In Go, function arguments, including those used in the defer statement, are evaluated at the time of the defer call, not at the actual execution time of the deferred function.

This means that if a variable is passed to defer, its value is fixed at the moment of the defer declaration, even if the deferred function is executed later, for example, after the function exits.

Example:

func example() (result int) {
    x := 5
    defer fmt.Println("defer x:", x) // x is fixed here, value is 5
    x = 10
    return x
}

When calling example(), the output will be "defer x: 5", even though at the return moment, x is already 10.

Regarding named return values, defer can modify them if the deferred function accesses them directly:

func example() (result int) {
    defer func() {
        result += 1 // modify the named result
    }()
    result = 5
    return // returns 6 after defer execution
}

Thus, defer fixes the argument values at the time of declaration but can influence the named return values if they are modified inside the deferred function.